Submission #1452485

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Source Code Expand

def solve():
    if N < M:
        return 'no'


    def saiki(A,B):

        if len(B) == 0:
            return 'yes'

        if len(A) == 0:
            return 'no'

        b = B[0]
        for (i, a) in enumerate(A):
            if b - a > T:
                continue
            if b - a < 0:
                return 'no'
            else: # b-a<=T
                break
        B = B[1:]
        A = A[i+1:]
        return saiki(A,B)

    return saiki(A,B)

print solve()

Submission Info

Judge Result